I just want to know how to set up. Cara is preparing an acid solution. She needs 200 milliliters of 48% concentration solution. Cara has 60% and 40% concentration solutions in her lab. How many milliliters of 40% acid solution should be mixed with 60% acid solution to make the required amount of 48% acid solution? Okay so these are the two equations I was trying. Where x=milliliters of 60% solution and y=milliliters of 40 percent solution X+Y=200 .6X+.4Y=200(.48) Thanks so much!!
paul2 Mathematics 1 0