14Jan

The ticket prices for a concert series were $12, $37, $45, $18, $8, $25, and $18. What was the ticket price of the eighth and final concert in this series if the set of 8 prices had a mean of $23, a mode of $18, and a median of $19.50?

lanceman1 Mathematics 1 6

The ticket prices for a concert series were $12, $37, $45, $18, $8, $25, and $18. What was the ticket price of the eighth and final concert in this series if the set of 8 prices had a mean of $23, a mode of $18, and a median of $19.50?

Posted by lanceman1 | Posted at Jan 14, 2020 | Categories: Mathematics

Answers

JamieJamieJamie
JamieJamieJamie

Given: 12, 37, 45, 18, 8, 25, 18, ? mean = 23 mode = 18 median = 19.50 using the mean 23 * 8 = 184 12 + 37 + 45 + 18 + 8 + 25 + 18 = 163 184 - 163 = 21 data set arranged in order from least to greatest: 8, 12, 18, 18, 21, 25, 37, 45 using the median 18 + 21 = 39 39 / 2 = 19.50 The missing ticket price is 21.

Jan 14, 2020 19:17

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