31Jan

A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before falling back down again.  A boy then catches the ball on the way down when it is 1.20 m above the pavement.  Ignoring air resistance, calculate the total amount of time the ball is in the air, from drop to catch.

takaragray Physics 1 0

A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before falling back down again.  A boy then catches the ball on the way down when it is 1.20 m above the pavement.  Ignoring air resistance, calculate the total amount of time the ball is in the air, from drop to catch.

Posted by takaragray | Posted at Jan 31, 2020 | Categories: Physics

Answers

krystiewise18
krystiewise18

The time the ball takes to fall 9.5 meters is the square root of (19/g), where g is gravitational acceleration. The time it takes to rise to 5.7 meters is the square root of (11.4/g), for the same value of g.  The time it takes to fall from 5.7 meters to 1.2 is the square root of (9/g).  So the answer is [sqrt(19)+sqrt(11.4)+sqrt(9)]/sqrt(g). If g=10, the answer is 3.39 seconds; if g=9.8, the answer is 3.43 seconds.

Jan 31, 2020 17:19

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