A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?

[latex]v_x=16,9frac{m}{s}\ s=44m\ g=10frac{m}{s^2}\\ v_x=frac{s}{t}Rightarrow t=frac{s}{v_x}\\ t=frac{44}{16,9}\\ t=2,6s\\ h=frac{gt^2}{2}\\ h=frac{10*2,6^2}{2}\\ h=5*6,76\\ h=33,8m[/latex]