05Jan

Вычислить (2√3)^2= √3*√18= 2√13*√2*5√26=

Yolpa Алгебра 2 17

Вычислить (2√3)^2= √3*√18= 2√13*√2*5√26=

Posted by Yolpa | Posted at Jan 05, 2014 | Categories: Алгебра

Answers

Александра00
Александра00

[latex](2 sqrt{3} )^2=2^{2} *( sqrt{3} )^2=4*3=12[/latex] [latex] sqrt{3} *sqrt{18} = sqrt{3*18} =sqrt{3*9*2} =3 sqrt{6} [/latex] [latex]2 sqrt{13} * sqrt{2} *5 sqrt{26} =2*5 sqrt{13*2*26} =10* sqrt{26*26} =10*26=260[/latex]

Jan 05, 2014 08:21
Puet49
Puet49

(2√3)^2=2²*(√3)²=4*3=12 √3*√18=√(3*√(9*2)=√3*3√2=3√(3*2)=3√6 2√13*√2*5√26=10*√(13*2*26)=10√(26²)=10*26=260

Jan 05, 2014 08:22

Leave a answer