05Jan

6a^3-6b^3 ---------------- = 3a^2 -3b^2 a=6,5; b=2,5

Шпилька Алгебра 1 17

6a^3-6b^3 ---------------- = 3a^2 -3b^2 a=6,5; b=2,5

Posted by Шпилька | Posted at Jan 05, 2014 | Categories: Алгебра

Answers

stepka24
stepka24

[latex] dfrac{6a^3-6b^3}{3a^2-3b^2}= dfrac{6(a-b)(a^2+ab+b^2)}{3(a+b)(a-b)}= dfrac{2a^2+2ab+2b^2}{3a+3b} [/latex] если а=6,5 а b=2,5, то [latex]dfrac{2*6,5^2+2*6,5*2,5+2*2,5^2}{3*6,5+3*2,5}=dfrac{84,5+32,5+12,5}{19,5+7,5}=dfrac{129,5}{27}=\=dfrac{1295}{270}=4dfrac{215}{270} [/latex]

Jan 05, 2014 08:56

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